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Download Chemical Engineering: Solutions to the Problems in Volume 1 by J R Backhurst, J H Harker, J. F. Richardson PDF

By J R Backhurst, J H Harker, J. F. Richardson

This quantity within the Coulson and Richardson sequence in chemical engineering comprises complete labored strategies to the issues posed in quantity 1. when the most quantity includes illustrative labored examples through the textual content, this booklet includes solutions to the more difficult questions posed on the finish of every bankruptcy of the most text.

those questions are of either a regular and non-standard nature, and so will turn out to be of curiosity to either educational employees educating classes during this quarter and to the willing pupil. Chemical engineers in who're trying to find a typical way to a real-life challenge also will locate the e-book of substantial curiosity.

* a useful resource of data for the scholar learning the fabric contained in Chemical Engineering quantity 1
* A important approach to studying - solutions are defined in complete

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Extra info for Chemical Engineering: Solutions to the Problems in Volume 1

Sample text

Calculate the drop in pressure. If the pressure drop falls by one half, what will be the new flowrate? Density of acid D 1840 kg/m3 . Viscosity of acid D 25 mN s/m2 . 00049 m2 . 00163 m3 /s. 32 m/s. 025/25 ð 10 3 D 6120 From Fig. 0043. 23 and Fig. 8 may be used to calculate the new flow. 02 ð 104 From Fig. 17 A Bingham plastic material is flowing under streamline conditions in a pipe of circular cross-section. What are the conditions for one half of the total flow to be within the central core across which the velocity profile is flat?

Partial section of concentric-cylinder viscometer which is established with the outer rotating and the inner stationary is less disturbed by centrifugal forces. The couple transmitted through the fluid to the suspended stationary inner cylinder is resisted by a calibrated spring, the deflection of which allows calculation of the torque, T, and hence the inner wall shearing stress Ri is given by: TD Ri ri 2 ri h This torque T originates from the outer cylinder which is driven at a uniform speed. 01 Nm which just produces motion at the surface of the inner cylinder.

0 1760 2670 3820 13000 24500 114600 These data may be plotted on linear axes as shown in Fig. 24 or on logarithmic axes as in Fig. 26 given here as Figs 3g and 3h, respectively. It will be seen from Fig. 122 jRy j From Fig. 3g, the slope is behaviour. 00028 m3 /s. 4 Ns/m2 5000 Intercept = 1500 N/m2 500 1000 1500 2000 0 3000 Shear rate (s−1) Figure 3g. Shear stress (N /m2) 100,000 10,000 1000 10 100 1000 Shear rate 10,000 100,000 (s−1) Figure 3h. (b) a large pump should force the material through the present line, or (c) a large pump should supply the liquid through a line of twice the cross-sectional area.

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